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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T20:45:31+00:00 2026-05-12T20:45:31+00:00

I’m trying to simply convert a byte received from fget into binary. I know

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I’m trying to simply convert a byte received from fget into binary.

I know the value of the first byte was 49 based on printing the value. I now need to convert this into its binary value.

unsigned char byte = 49;// Read from file
unsigned char mask = 1; // Bit mask
unsigned char bits[8];

  // Extract the bits
for (int i = 0; i < 8; i++) {
    // Mask each bit in the byte and store it
    bits[i] = byte & (mask << i);
}
 // For debug purposes, lets print the received data
for (int i = 0; i < 8; i++) {
printf("Bit: %d\n",bits[i]);
}

This will print:

Bit: 1
Bit: 0
Bit: 0
Bit: 0
Bit: 16
Bit: 32
Bit: 0
Bit: 0
Press any key to continue . . .

Clearly, this is not a binary value. Any help?

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  1. Editorial Team
    Editorial Team
    2026-05-12T20:45:31+00:00Added an answer on May 12, 2026 at 8:45 pm

    The problem you’re having is that your assignment isn’t resulting in a true or false value.

    bits[i] = byte & (mask << i);
    

    This gets the value of the bit. You need to see if the bit is on or off, like this:

    bits[i] = (byte & (mask << i)) != 0;
    
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