Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7584425
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 30, 20262026-05-30T18:55:03+00:00 2026-05-30T18:55:03+00:00

I’m trying to solve my LazyLoading problem, which I worked around by fetchType EAGER

  • 0

I’m trying to solve my LazyLoading problem, which I worked around by fetchType EAGER in the past. But that cannot be the final solution.

I tried to contruct an example, which does not make much sence the way it is, but demonstrates my problem:
I have a company, and persons are @ManyToOne by composition.
Now when I try to access the personList by a calculator, I get this exception:

Schwerwiegend [javax.enterprise.resource.webcontainer.jsf.context] (http--127.0.0.1-8080-4) javax.el.ELException: /tablePersons.xhtml @31,76 value=" #{calculator.getPersonCount(_var)}":
org.hibernate.LazyInitializationException: failed to lazily initialize a collection of role: business.domain.Company.personList, no session or session was closed

Maybe someone can help me solving this?

tablePersons.xhtml:

<p:dataTable var="_var" value="#{facade.companies}">
<p:column>
<h:outputText value="#{calculator.getPersonCount(_var)}" />

backing facades:

@Named
@RequestScoped
class Facade() {
    @Inject
    Dao dao;

    List<Company> companies;

    @PostConstruct
    init() {
        companies = Dao.findByNamedQuery("Companies.ALL");
    }
}


@Named
@RequestScoped
class Calculator {
    int getPersonCount(Company c) {
        return c.getPersonList().size(); //EX
    }
}

Crud service:

@Stateless
@Transactional
class Dao() {
    @PersistenceContext
    private EntityManager em;

    //CRUD
}

Entity:

@Entity
@NamedQueries( {
    @NamedQuery(name = Company.ALL",
                query = "SELECT c FROM Company c")
})
class Company {
    @OneToMany(cascade = CascadeType.ALL)  // fetch=FetchType.EAGER <-ugly, but would work
    List<Person> personList = new LinkedList<Person>();
}

I also already configured the Spring OpenEntityManager in web.xml:

<filter>
    <filter-name>OpenEntityManagerInViewFilter</filter-name>
    <filter-class>
        org.springframework.orm.jpa.support.OpenEntityManagerInViewFilter
    </filter-class>
    <init-param>
        <param-name>entityManagerFactoryBeanName</param-name>
        <param-value>entityManagerFactory</param-value>
    </init-param>
</filter>
<filter-mapping>
    <filter-name>OpenEntityManagerInViewFilter</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

Nevertheless it does not work. But I have not more idea why!
Maybe someone knows more?

tyvm

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-30T18:55:04+00:00Added an answer on May 30, 2026 at 6:55 pm

    To solve the LazyInitializationException occurs in the view layer , you have the following options:

    1. Use “Open EntityManager in View” pattern to lazy load the uninitialized entities in the view .It seems that you are doing this way , but I have no idea why it is failed.

    2. Before returning to the view , always initialize all the entities that are required to be displayed in the view .

    You can use Hibernate.initialize() to force initializing the Company.personList :

    class Facade() {
        @Inject
        Dao dao;
    
        List<Company> companies;
    
        @PostConstruct
        init() {
            companies = Dao.findByNamedQuery("Companies.ALL");
            Hibernate.initialize(companies.getPersonList()); 
        }
    } 
    

    Or use the fetch join to fetch the personList along with the Company.It will cause the returned Companies object have their personList fully initialized.

    @Entity
    @NamedQueries( {
        @NamedQuery(name = "Company.ALL",query = "SELECT c FROM Company c")
        @NamedQuery(name = "Company.ALL.WithPerson",query = "SELECT c FROM Company c join fetch c.personList")
    })
    class Company {
        @OneToMany(cascade = CascadeType.ALL)  // fetch=FetchType.EAGER <-ugly, but would work
        List<Person> personList = new LinkedList<Person>();
    }
    

    Then retrieve the company using the named query “Company.ALL.WithPerson”

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I am trying to understand how to use SyndicationItem to display feed which is
Seemingly simple, but I cannot find anything relevant on the web. What is the
I have a French site that I want to parse, but am running into
I'm parsing an RSS feed that has an &#8217; in it. SimpleXML turns this
I'm trying to decode HTML entries from here NYTimes.com and I cannot figure out
I'm trying to create an if statement in PHP that prevents a single post
Basically, what I'm trying to create is a page of div tags, each has
link Im having trouble converting the html entites into html characters, (&# 8217;) i
That's pretty much it. I'm using Nokogiri to scrape a web page what has
I want to count how many characters a certain string has in PHP, but

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.