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Home/ Questions/Q 7695119
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T21:28:34+00:00 2026-05-31T21:28:34+00:00

I’m trying to solve this newbie puzzle: I’ve created this function: def bucket_loop(htable, key):

  • 0

I’m trying to solve this newbie puzzle:

I’ve created this function:

def bucket_loop(htable, key):
    bucket = hashtable_get_bucket(htable, key)
    for entry in bucket:
        if entry[0] == key:          
            return entry[1]                         
    return None

And I have to call it in two other functions (bellow) in the following way: to change the value of the element entry[1] or to append to this list (entry) a new element. But I can’t do that calling the function bucket_loop the way I did because “you can’t assign to function call” (assigning to a function call is illegal in Python). What is the alternative (most similar to the code I wrote) to do this (bucket_loop(htable, key) = value and hashtable_get_bucket(htable, key).append([key, value]))?

def hashtable_update(htable, key, value):
    if bucket_loop(htable, key) != None:
        bucket_loop(htable, key) = value
    else:
        hashtable_get_bucket(htable, key).append([key, value])

def hashtable_lookup(htable, key):
    return bucket_loop(htable, key)

Thanks, in advance, for any help!

This is the rest of the code to make this script works:

def make_hashtable(size):
    table = []
    for unused in range(0, size):
        table.append([])
    return table

def hash_string(s, size):
    h = 0
    for c in s:
         h = h + ord(c)
    return h % size

def hashtable_get_bucket(htable, key):
    return htable[hash_string(key, len(htable))]

Similar question (but didn’t help me): SyntaxError: "can't assign to function call"

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T21:28:35+00:00Added an answer on May 31, 2026 at 9:28 pm

    In general, there are three things you can do:

    1. Write “setter” functions (ex, bucket_set)
    2. Return mutable values (ex, bucket_get(table, key).append(42) if the value is a list)
    3. Use a class which overrides __getitem__ and __setitem__

    For example, you could have a class like like:

    class Bucket(object):
        def __setitem__(self, key, value):
            # … implementation …
        def __getitem__(self, key):
            # … implementation …
            return value
    

    Then use it like this:

    >>> b = Bucket()
    >>> b["foo"] = 42
    >>> b["foo"]
    42
    >>> 
    

    This would be the most Pythonic way to do it.

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