Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8580105
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 11, 20262026-06-11T20:45:23+00:00 2026-06-11T20:45:23+00:00

I’m trying to subtract 2 character vectors containing date time information in the following

  • 0

I’m trying to subtract 2 character vectors containing date time information in the following format:

train2 <- data.frame(
  time2 = c(
    "2011-09-01 23:44:52.533", "2011-09-05 12:25:37.42", "2011-08-24 12:56:58.91",
    "2011-10-25 07:18:14.722", "2011-10-25 07:19:51.697"
  ),
  time3 = c(
    "2011-09-01 23:43:59.752", "2011-09-05 12:25:01.187",
    "2011-08-24 12:55:13.012", "2011-10-25 07:16:51.759",
    "2011-10-25 07:16:51.759"
  )
)

I’ve hunted around and played with zoo, as.Date, as.POSIXct, etc. to try and find the correct code to subtract 2 datetime objects and get an answer in seconds but without luck.

I’d appreciate any suggestions.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-11T20:45:24+00:00Added an answer on June 11, 2026 at 8:45 pm

    Easy peasy:

    R> now <- Sys.time()
    R> then <- Sys.time()
    R> then - now
    Time difference of 5.357 secs
    R> class(then - now)
    [1] "difftime"
    R> as.numeric(then - now)
    [1] 5.357
    R> 
    

    And for your data:

    R> df
                        time2                   time3
    1 2011-09-01 23:44:52.533 2011-09-01 23:43:59.752
    2  2011-09-05 12:25:37.42 2011-09-05 12:25:01.187
    3  2011-08-24 12:56:58.91 2011-08-24 12:55:13.012
    4 2011-10-25 07:18:14.722 2011-10-25 07:16:51.759
    5 2011-10-25 07:19:51.697 2011-10-25 07:16:51.759
    R> df$time2 <- strptime(df$time2, "%Y-%m-%d %H:%M:%OS")
    R> df$time3 <- strptime(df$time3, "%Y-%m-%d %H:%M:%OS")
    R> df
                        time2                   time3
    1 2011-09-01 23:44:52.533 2011-09-01 23:43:59.752
    2 2011-09-05 12:25:37.420 2011-09-05 12:25:01.187
    3 2011-08-24 12:56:58.910 2011-08-24 12:55:13.012
    4 2011-10-25 07:18:14.722 2011-10-25 07:16:51.759
    5 2011-10-25 07:19:51.697 2011-10-25 07:16:51.759
    R> df$time2 - df$time3
    Time differences in secs
    [1]  52.781  36.233 105.898  82.963 179.938
    attr(,"tzone")
    [1] ""
    R> 
    

    and added back as a numeric to the data frame:

    R> df$dt <- as.numeric(df$time2 - df$time3)
    R> df
                        time2                   time3      dt
    1 2011-09-01 23:44:52.533 2011-09-01 23:43:59.752  52.781
    2 2011-09-05 12:25:37.420 2011-09-05 12:25:01.187  36.233
    3 2011-08-24 12:56:58.910 2011-08-24 12:55:13.012 105.898
    4 2011-10-25 07:18:14.722 2011-10-25 07:16:51.759  82.963
    5 2011-10-25 07:19:51.697 2011-10-25 07:16:51.759 179.938
    R> 
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I want to construct a data frame in an Rcpp function, but when I
I'm trying to use string.replace('’','') to replace the dreaded weird single-quote character: ’ (aka
I am trying to understand how to use SyndicationItem to display feed which is
Basically, what I'm trying to create is a page of div tags, each has
link Im having trouble converting the html entites into html characters, (&# 8217;) i
I have a string like this: La Torre Eiffel paragonata all&#8217;Everest What PHP function
I am trying to render a haml file in a javascript response like so:
I have this code to decode numeric html entities to the UTF8 equivalent character.
I'm using v2.0 of ClassTextile.php, with the following call: $testimonial_text = $textile->TextileRestricted($_POST['testimonial']); ... and
I'm parsing an RSS feed that has an &#8217; in it. SimpleXML turns this

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.