Question

I’m trying to take a long sting and extract all the urls it contains.

page.findall(r"http://.+")

is what I have, but that doesn’t result in what I want. The urls are all wrapped in double quotes, so how can I tell regular expressions to stop matching when it reaches a “?

Answer 1

There are very complex url-parsing regexes out there, but if you want to stop at a ", just use [^\"]+ for the url part.

Or switch to a single-quoted string and remove the \.

Also, if you have https mixed in, it will break, so you might want to just go with

page.findall(r'"(http[^"]+)"')

But now we’re getting into url-parsing regexes.