Question

I’m trying to take a MySQL result row and pass it to a function for processing but the row isn’t getting passed. I’m assuming this is because the actual row comes back as a object and objects can’t get passed to function?

E.G

function ProcessResult($TestID,$Row){
    global $ResultArray;
    $ResultArray["Sub" . $TestID] = $Row["Foo"] - $Row["Bar"];
    $ResultArray["Add" . $TestID] = $Row["Foo"] + $Row["Bar"];
}



$SQL = "SELECT TestID,Foo,Bar FROM TestResults WHERE TestDate !='0000-00-00 00:00:00'";
$Result= mysql_query($SQL$con);

    if(!$Result){
        // SQL Failed
        echo "Couldn't find how many tests to get";
    }else{

        $nRows = mysql_num_rows($Result);

        for ($i=0;$i<$nRows;$i++)
        {
            $Row = mysql_fetch_assoc($Result);

            $TestID = $Row[TestID];

            ProcessResult($TestID,$Row);
        }

    }

What I need is $ResultArray populated with a load of data from the MySQL query. This isn’t my actual application (I know there’s no need to do this for what’s shown) but the principle of passing the result to a function is the same.

Is this actually possible to do some how?

Dan

Answer 1

mysql_query($SQL$con); should be mysql_query($SQL,$con); The first is a syntax error. Not sure if this affects your program or if it was just a typo on here.

I would recommend putting quotes around your array keys. $row[TestID] should be $row["TestID"]

The rest looks like it should work, although there are some strange ideas going on here.

Also you can do this to make your code a little cleaner.

if(!$Result){
    // SQL Failed
    echo "Couldn't find how many tests to get";
}else{

    while($Row = mysql_fetch_assoc($Result))
    {
        $TestID = $Row['TestID'];

        ProcessResult($TestID,$Row);
    }

}