Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7780483
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 1, 20262026-06-01T18:54:45+00:00 2026-06-01T18:54:45+00:00

I’m trying to test a sql database that I created. To do so, I’ve

  • 0

I’m trying to test a sql database that I created. To do so, I’ve got 2 tables: items and brands. Items store different fields including the name of a brand, and brands store other fields including a name. I would like to check that for each brand in items, there is a corresponding name in brands table. How would I do that ? I thought of something along the lines of:

"for each row in items"
if (count(select * from items join brands on items.brand = brands.name) == 0, select items.name, '');

But then I don’t know how to include the for statement in it… Any ideas?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-01T18:54:48+00:00Added an answer on June 1, 2026 at 6:54 pm

    You could try this:

    SELECT items.name 
    FROM items LEFT JOIN brands
        ON items.brand = brands.name
    WHERE brands.name IS NULL
    ORDER BY items.name
    

    With this query you get all records from items table, join them with corresponing brands records (if they exists) and finally take the ones not having brands corresponding record.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I've got a string that has curly quotes in it. I'd like to replace
I'm parsing an RSS feed that has an ’ in it. SimpleXML turns this
I'm trying to create an if statement in PHP that prevents a single post
I am trying to understand how to use SyndicationItem to display feed which is
Basically, what I'm trying to create is a page of div tags, each has
link Im having trouble converting the html entites into html characters, (&# 8217;) i
That's pretty much it. I'm using Nokogiri to scrape a web page what has
I have a string like this: La Torre Eiffel paragonata all’Everest What PHP function
I am trying to render a haml file in a javascript response like so:
I am doing a simple coin flipping experiment for class that involves flipping a

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.