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Home/ Questions/Q 9205145
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T23:53:00+00:00 2026-06-17T23:53:00+00:00

I’m trying to think of a solution to a mapping problem in which I

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I’m trying to think of a solution to a mapping problem in which I can relate two seemingly unrelated groups. So, lets say I have a set of attributes, A, an Entity Group 1, and an Entity Group 2. I could easily have a many-many relationship between 1 and A and do queries like

select * from 1 
  inner join a_1 on a_1.1_id = 1.id
  inner join a on a.id = a_1.a_id
  where a.attr = '123'

I could obviously do something similar with A related to 2. What I’m trying to actually query though is A to 2 and A to 1 where the elements in group 1 and 2 share the same attribute in A. So, if the attribute I’m storing is an address, I want to be able to select out all people in group 1 and group 2 that share addresses, and what those addresses are.

Appreciate the help!

EDIT:

Table structure:

t1 -----< t1_A >------ A ------< t2_A >------ t2

t1[id, other], t1_A[id, t1id, Aid], A[id, address], t2_A[id, t2id, Aid], t2[id, other]

And the goal is to get a row returned for every element in t1 that has the same address as an element in t2(as well as what that address is).

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T23:53:01+00:00Added an answer on June 17, 2026 at 11:53 pm

    query though is A to 2 and A to 1 where the elements in group 1 and 2
    share the same attribute in A.

    I think you are looking for UNION:

    select address, ... -- and other properties
    from table1 t1 
    inner join a on a.a_id = t1.id
    where a.attr = '123'
    UNION ALL
    select address, ... -- and other properties
    from table2 t2 
    inner join a on a.a_id = t2.id
    where a.attr = '123'
    

    Update:

    Considering the tables’ structures, after updating your question:

    t1:

    • id,
    • …

    t1_A:

    • id,
    • t1id,
    • Aid,
    • …

    A:

    • id,
    • address,
    • …

    t2_A:

    • id,
    • t2id,
    • Aid,
    • …

    t2:

    • id,
    • …

    So, you want to get:

    And the goal is to get a row returned for every element in t1 that has
    the same address as an element in t2(as well as what that address is).

    Then you can do this:

    SELECT
      t1.*,
      A.*
    FROM t1
    INNER JOIN t1_A ON t1.id = t1_A.t1id
    INNER JOIN A    ON A.id  = t1_A.Aid
    INNER JOIN t2_A ON a.id  = t2_A.aid
    INNER JOIN t2   ON t2.id = t2_A.t2id;
    
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