Question

Im trying to throw something together in PHP. I can’t seem to get this simple bit to work.

The result I want is if $x = 4, 5, or 6 the output should be hello x is (the value of $x)

here is the code:

<?php
    $x = 1;
if ($x != 4 || $x != 5 || $x != 6)
    {echo "hello ";
    echo "x is $x";}
 ?>

In the example above the output is “hello x is 1”

however if I change the first line of the code to $x = 4 the expected output is “hello x is 4” when the output should be blank.

Thanks,
Chris

Answer 1

You have the opposite logic. You need

if ($x == 4 || $x == 5 || $x == 6)