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Home/ Questions/Q 7704621
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T23:43:19+00:00 2026-05-31T23:43:19+00:00

I’m trying to tilt an image 90 degrees, currently I’m following the method presented

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I’m trying to tilt an image 90 degrees, currently I’m following the method presented here:
http://www.scribd.com/doc/66589491/Image-Rotation-Using-CUDA

My current code for the kernel is this:

 __global__ void kernCuda(float *Source,float * Destination, int width)
{
    int x = blockIdx.x * blockDim.x + threadIdx.x;
    int y = blockIdx.y * blockDim.y + threadIdx.y; 

    int i = abs(x*cosf(theta)-y*sinf(theta));
    int j = abs(x*sinf(theta)+y*cosf(theta));

    if(x<width && y<width){
        Destination[j*width+i]=Source[y*width+x];
    }

}

The image tilts somewhat, however it seems like it is not correct, on top of that some pixels that are colored is now black(0). Any help would be appreciated

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  1. Editorial Team
    Editorial Team
    2026-05-31T23:43:20+00:00Added an answer on May 31, 2026 at 11:43 pm

    I assume that theta is a floating point number. So you are mixing floating point and integer variables. I would suggest you use the appropriate casts to make it work and look for rounding issues.

    Secondly, in order to see whether your program works in general you can replace cosf(theta) by 0 and sinf(theta) by 1.

    One third issue that I can see is that you only take one x,y value instead of looping over them by using a while loop. So in case your image dimension is larger than the kernel that you use, you will not get all your pixels.

    Edit: I just had a brief look at the report. It really is not very good. If you want to just learn about CUDA I suggest you get the book called “CUDA by Example”.

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