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Home/ Questions/Q 6553277
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T12:33:45+00:00 2026-05-25T12:33:45+00:00

I’m trying to translate some python code to scala code. So I’m a total

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I’m trying to translate some python code to scala code. So I’m a total noob in Python.

But why do some classes have object as a parameter but never explicitly use it? What’s the reasoning for having it as a parameter in the first place?

Example:

class Table(object)

Thank you for your time.

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  1. Editorial Team
    Editorial Team
    2026-05-25T12:33:46+00:00Added an answer on May 25, 2026 at 12:33 pm

    In Python2 this declares Table to be a new-style class (as opposed to “classic” class).
    In Python3 all classes are new-style classes, so this is no longer necessary.

    New style classes have a few special attributes that classic classes lack.

    class Classic: pass
    class NewStyle(object): pass
    
    print(dir(Classic))
    # ['__doc__', '__module__']
    
    print(dir(NewStyle))
    # ['__class__', '__delattr__', '__dict__', '__doc__', '__format__', '__getattribute__', '__hash__', '__init__', '__module__', '__new__', '__reduce__', '__reduce_ex__', '__repr__', '__setattr__', '__sizeof__', '__str__', '__subclasshook__', '__weakref__']
    

    Also, properties and super do not work with classic classes.

    In Python2 it is a good idea to make all classes new-style classes. (Though a lot of classes in the standard library are still classic classes, for the sake of backward-compatibility.)

    In general, in a statement such as

    class Foo(Base1, Base2):
    

    Foo is being declared as a class inheriting from base classes Base1 and Base2.

    object is the mother of all classes in Python. It is a new-style class, so inheriting from object makes Table a new-style class.

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