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Home/ Questions/Q 3681306
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T03:40:31+00:00 2026-05-19T03:40:31+00:00

I’m trying to understand how my PHP script can pass an array to my

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I’m trying to understand how my PHP script can pass an array to my JavaScript code. Using the following PHP, I pass an array:

$c = array(3,2,7);

echo json_encode($c);

My JavaScript is as follows:

    $.post("getLatLong.php", { latitude: 500000},
        function(data) {
            arrayData = data
            document.write(arrayData)
            document.write(arrayData[0]);
            document.write(arrayData[0]);
            document.write(arrayData[0]);
        });
</script>

What is printed out on the screen is

[3,2,7][3,

I’m trying to understand how json_encode works – I thought I would be able to pass the array to a variable, and then access it like a normal JavaScript array, but it views my array as one large text string. How do ensure that it reads it like an array?

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  1. Editorial Team
    Editorial Team
    2026-05-19T03:40:32+00:00Added an answer on May 19, 2026 at 3:40 am

    Pass the dataType argument to $.post:

    $.post("getLatLong.php", { latitude: 500000},
       function(data){         
       // ...
    }, 'json');
    

    Then data will be properly decoded.

    Alternatively you can also use $.parseJSON in the callback.

    Explanation of JSON:

    JSON is a data exchange format. It specifies the structure of the data string that is transmitted. json_encode takes a PHP data structure like an array or an object and transformes it to JSON, i.e. a string with a certain format.

    json_encode($c) will give you the string "[3,2,7]".

    On the client site, you receive that string, but you have to decode it in to proper JavaScript data structures. So $.parseJSON(data) will give you a JavaScript array with 3 elements (or if you pass ‘json’ as third parameter to .post(), jQuery is doing the decoding automatically for you).

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