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Home/ Questions/Q 8219509
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T13:11:28+00:00 2026-06-07T13:11:28+00:00

I’m trying to understand how PHP manages memory and variables with static methods in

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I’m trying to understand how PHP manages memory and variables with static methods in extended classes. I’ve got three classes one entitled Model, User1, User2. Hence:

class Model {
    static public $structure;
    static public $name;
    static function get_structure() {
        return self::$structure = file_get_contents(self::$name.'.json');
    }
}
class User1 extends Model {

}
class User2 extends Model {

}
User1::$name = 'User1';
User2::$name = 'User2';
echo User1::get_structure();
echo User2::get_structure();

If I run User1::get_structure(); for some reason it doesn’t populate the result accordingly, it seems to be grabbing the value of User2 (the last $name value declared).

I’m operating on the assumption that declaring User2 and extending Model creates a completely separate scope for my $name property. So User1 and User2 are declared as separate classes with the same structure as Model. Then I can statically define values for them in separate scopes.

I’m now however questioning that. If I extend and call the same $name variable do they both point back to the Model class? Or does it only create a separate scope when I declare each class with new User1(); and new User2();?

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-06-07T13:11:29+00:00Added an answer on June 7, 2026 at 1:11 pm

    You get this behavior, because you are accessing same variable

    class X
    {
        public static $data = null;
    }
    
    class Foo extends X{};
    class Bar extends X{};
    
    Foo::$data = 'lorem ipsum';
    echo Bar::$data;
    // :: output :: lorem ipsum;
    

    Your $name variable stays tied to the Model class, even in inherited classes.

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