I’m trying to understand how the quaternion rotations work, I found this mini tutorial http://www.julapy.com/blog/2008/12/22/quaternion-rotation/ but He makes some assumptions that I can’t workout, like how can I do “work out the rotation vectors around each axis, simply by rotating the vector around an axis.” and how does he calculate angleDegreesX, angleDegreesY and angleDegreesZ?
Can some one provide a working example or explanation?
The shortest possible summary is that a quaternion is just shorthand for a rotation matrix. Whereas a 4×4 matrix requires 16 individual values, a quaternion can represent the exact same rotation in 4.
For the mathematically inclined, I am fully aware that the above is super over-simplified.
To provide a little more detail, let’s refer to the Wikipedia article:
What isn’t clear from that opening paragraph is that a quaternion is not only convenient, it’s unique. If you have a particular orientation of an object, twisting on any number of axes, there exists a single unique quaternion that represents that orientation.
Again, for the mathematically inclined, my uniqueness comment above assumes right-handed rotations. There is an equivalent left-handed quaternion that rotates in the opposite direction around the opposite axis.
For the purpose of simple explanation, that is something of a distinction without a difference.
If you’d like to make a simple quaternion that represents rotation about an axis, here’s a short series of steps that will get you there:
v = {x, y, z}. Just for politeness, please pick a unit vector: if it’s not already of length 1, divide all the components by the length of v.theta.Quaternion construction:
Note those divisions by two: those ensure that there’s no confusion in the rotation. With a normal rotation matrix, rotating to the right 90 degrees is the same as rotating to the left by 270. The quaternions that are equivalent to those two rotations are distinct: you can’t confuse one with the other.
EDIT: responding to the question in the comments:
Let’s simplify the problem by setting the following frame of reference:
So, if we have an example object (say an arrow) that starts by pointing to the right (positive x axis). If we move the mouse up from the x axis, the mouse will provide us with a positive x and positive y. So, working through the series of steps: