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Home/ Questions/Q 4267226
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T06:52:14+00:00 2026-05-21T06:52:14+00:00

I’m trying to understand the array setup in java. Why must you initialize space

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I’m trying to understand the array setup in java. Why must you initialize space for each each object in the array, after you have created the array. How is it stored in memory like this:

[object][object]

or like this:

[*class]->[object]  
[*class]->[object]

In other words, what is actually being done in memory. Does array[0] = new class() just return a reference to a reserved location in memory, and the class[] array = new class[10] statement create something along the lines of 10 pointers, which are later assigned to by the new statements?

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  1. Editorial Team
    Editorial Team
    2026-05-21T06:52:15+00:00Added an answer on May 21, 2026 at 6:52 am

    Arrays in Java store one of two things: either primitive values (int, char, …) or references (a.k.a pointers).

    So, new Integer[10] creates space for 10 Integer references only. It does not create 10 Integer objects (or even free space for 10 Integer objects).

    Incidentally that’s exactly the same way that fields, variables and method/constructor parameters work: they too only store primitive values or references.

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