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Home/ Questions/Q 6604579
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T19:10:33+00:00 2026-05-25T19:10:33+00:00

I’m trying to understand the difference between *(1..9) and [*1..9] If I assign them

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I’m trying to understand the difference between *(1..9) and [*1..9]

If I assign them to variables they work the same way

splat1 = *(1..9)  # splat1 = [1, 2, 3, 4, 5, 6, 7, 8, 9]
splat2 = [*1..9]  # splat2 = [1, 2, 3, 4, 5, 6, 7, 8, 9]

But things get weird when I try to use *(1..9) and [*1..9] directly.

*(1..9).map{|a| a.to_s}  # syntax error, unexpected '\n', expecting tCOLON2 or '[' or '.'
[*1..9].map{|a| a.to_s}  # ["1", "2", "3"...]

I’m guessing part of the problem is with operator precidence? But I’m not exactly sure what’s going on. Why am I unable to use *(1..9) the same I can use [*1..9]?

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  1. Editorial Team
    Editorial Team
    2026-05-25T19:10:34+00:00Added an answer on May 25, 2026 at 7:10 pm

    I believe the problem is that splat can only be used as an lvalue, that is it has to be received by something.

    So your example of *(1..9).map fails because there is no recipient to the splat, but the [*1..9].map works because the array that you are creating is the recipient of the splat.

    UPDATE:
    Some more information on this thread (especially the last comment): Where is it legal to use ruby splat operator?

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