Question

I’m trying to use a regular expression to select all of each word except the first character, much as @mahdaeng wanted to do here. The solution offered to his question was to use \B[a-z]. This works fine, except when a word contains some form of punctuation, such as “Jack’s” and “merry-go-round”. Is there a way to select the entire word including any contained punctuation? (Not including outside punctuation such as “? , .” etc.)

Answer 1

If you can enumerate the acceptable in-word punctuation, you could just expand upon the answer you linked:

\B[a-zA-Z'-]+