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Home/ Questions/Q 4619032
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T02:22:08+00:00 2026-05-22T02:22:08+00:00

I’m trying to use a variable as a command’s parameter but can’t quite figure

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I’m trying to use a variable as a command’s parameter but can’t quite figure it out. Let’s say MyCommand will accept two parameters: option1 and option2 and they accept boolean values. How would I use $newVar to substitute option 1 or 2? For example:

$newVar = "option1"
MyCommand -$newVar:$true

I keep getting something along the lines of ‘A positional parameter cannot be found that accepts argument ‘-System.String option1’.


More Specifically:
Here, the CSV file is an output of a different policy. The loop goes through each property in the file and sets that value in my policy asdf; so -$_.name:$_.value should substitute as -AllowBluetooth:true.

Import-Csv $file | foreach-object {
    $_.psobject.properties | where-object {
    # for testing I'm limiting this to 'AllowBluetooth' option
    if($_.name -eq "AllowBluetooth"){
    Set-ActiveSyncMailboxPolicy -Identity "asdf" -$_.name:$_.value
    }}
}
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  1. Editorial Team
    Editorial Team
    2026-05-22T02:22:09+00:00Added an answer on May 22, 2026 at 2:22 am

    Typically to use a variable to populate cmdlet parameters, you’d use a hash table variable, and splat it, using @

     $newVar = @{option1 = $true}
     mycommand @newVar
    

    Added example:

    $AS_policy1 = @{
    Identity = "asdf"
    AllowBluetooth = $true
    }
    
    Set-ActiveSyncMailboxPolicy @AS_policy1
    
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