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Home/ Questions/Q 615055
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T18:10:42+00:00 2026-05-13T18:10:42+00:00

I’m trying to use an overloaded >> to scan input from a file. The

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I’m trying to use an overloaded “>>” to scan input from a file.

The problem is, I have no idea how to deal with end of file.
In this case, my file is composed of a number, followed by several chars

Ex:

9rl

8d

6ff

istream &operator>>(istream &is, Move &move)
{
  char c;
  int i = 0;

  c = is.get();

  if (!isalnum(c))
      return;

  move.setNum(c); // I convert the char to an int, but I'l edit it out

  while ( (c = is.get()) != '\n')
  {
    move.setDirection(i, c); //sets character c into in array at index i
    i++;

  } // while chars are not newline

  return is;
} // operator >>

The test for the character being alpha numeric worked when I had this as a regular function, but doesn’t work here as it expects an input stream to be returned. I’ve tried returning NULL as well. Suggestions?

EDIT: this is being called in a while loop, So i’m trying to figure out some way to have this trigger some flag so that I can break out of the loop. In my previous function, I had this return a boolean, returning true if successful or false if the character was not alphanumeric

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T18:10:42+00:00Added an answer on May 13, 2026 at 6:10 pm

    Return is. Callers should check the stream for errors.

    Be sure to set error bits as appropriate:

    std::istream &operator>>(std::istream &is, Move &move)
    {
      char c;
      int i = 0;
    
      c = is.get();
      if (is.eof())
        return is;
      else if (c < '0' || c > '9') {
        is.setstate(std::ios::badbit);
        return is;
      }
      else
        move.setNum(c-'0');
    
      while ( (c = is.get()) != '\n' && is)
        move.setDirection(i++, c);
    
      if (c != '\n')
        is.setstate(std::ios::badbit);
      return is;
    }
    

    Use it as in the following:

    int main(int argc, char **argv)
    {
      std::stringstream s;
    
      s << "9rl\n"
        << "8d\n"
        << "6ff\n";
      s.seekg(0);
    
      Move m;
      while (s >> m)
        std::cout << m;
    
      if (s.bad())
        std::cerr << argv[0] << ": extraction failed\n";
    
      return 0;
    }
    

    Notice that the code uses the instance m only after successful extraction.

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