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Home/ Questions/Q 830337
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T04:01:41+00:00 2026-05-15T04:01:41+00:00

I’m trying to use Java ( not XML ) to create a LinearLayout with

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I’m trying to use Java (not XML) to create a LinearLayout with buttons that fill the screen, and have margins. Here is code that works without margins:

LinearLayout buttonsView = new LinearLayout(this);
buttonsView.setOrientation(LinearLayout.VERTICAL);
for (int r = 0; r < 6; ++r) {
    Button btn = new Button(this);
    btn.setText("A");

    LinearLayout.LayoutParams lp = new LinearLayout.LayoutParams(LinearLayout.LayoutParams.FILL_PARENT, LinearLayout.LayoutParams.FILL_PARENT); // Verbose!
    lp.weight = 1.0f; // This is critical. Doesn't work without it.
    buttonsView.addView(btn, lp);
}

ViewGroup.LayoutParams lp = new ViewGroup.LayoutParams(ViewGroup.LayoutParams.FILL_PARENT, ViewGroup.LayoutParams.FILL_PARENT);
setContentView(buttonsView, lp);

So that works fine, but how on earth do you give the buttons margins so there is space between them? I tried using LinearLayout.MarginLayoutParams, but that has no weight member so it’s no good. And it doesn’t work if you pass it lp in its constructor either.

Is this impossible? Because it sure looks it, and it wouldn’t be the first Android layout task you can only do in XML.

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  1. Editorial Team
    Editorial Team
    2026-05-15T04:01:41+00:00Added an answer on May 15, 2026 at 4:01 am

    Here is a little code to accomplish it:

    LinearLayout ll = new LinearLayout(this);
    ll.setOrientation(LinearLayout.VERTICAL);
    
    LinearLayout.LayoutParams layoutParams = new LinearLayout.LayoutParams(
         LinearLayout.LayoutParams.MATCH_PARENT, LinearLayout.LayoutParams.WRAP_CONTENT);
    
    layoutParams.setMargins(30, 20, 30, 0);
    
    Button okButton=new Button(this);
    okButton.setText("some text");
    ll.addView(okButton, layoutParams);
    
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