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Home/ Questions/Q 7811387
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T04:08:37+00:00 2026-06-02T04:08:37+00:00

I’m trying to use LINQ and I keep getting this error message: Operator ‘<‘

  • 0

I’m trying to use LINQ and I keep getting this error message:

Operator ‘<‘ cannot be applied to operands of type ‘Ilistprac.Location’ and ‘int’

I tried an override but I get an error message:

‘Ilistprac.Location.ToInt()’: no suitable method found to override

All the IList interfaces are implemented with the IEnurmerable too (just not listed here unless someone wants me to).

class IList2
{
    static void Main(string[] args)
    {

     Locations test = new Locations();
     Location loc = new Location();
     test.Add2(5);
     test.Add2(6);
     test.Add2(1);
     var lownumes = from n in test where (n < 2) select n;


     }
 }

public class Location
{
    public Location()
    {

    }
    private int _testnumber = 0;
    public int testNumber
    {
        get { return _testnumber; }
        set { _testnumber = value;}
    }

public class Locations : IList<Location>
{
    List<Location> _locs = new List<Location>();

    public Locations() { }

  public void Add2(int number)
    {
        Location loc2 = new Location();
        loc2.testNumber = number;
        _locs.Add(loc2);
    }

 }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-02T04:08:39+00:00Added an answer on June 2, 2026 at 4:08 am

    You either want to compare n.testNumber or you need to overload the < operator in the Location class so you can actually compare it to an int.

    public class Location
    {
        public Location()
        {
    
        }
    
        private int _testnumber = 0;
        public int testNumber
        {
            get { return _testnumber; }
            set { _testnumber = value;}
        }
    
        public static bool operator <(Location x, int y) 
        {
            return x.testNumber < y;
        }
    
        public static bool operator >(Location x, int y) 
        {
            return x.testNumber > y;
        }
     }
    
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