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Editorial Team
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Asked: 2026-06-04T03:44:08+00:00

I’m trying to use regex to replace source attribute (could be image or any

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I’m trying to use regex to replace source attribute (could be image or any tag) in PHP.

I’ve a string like this:

$string2 = "<html><body><img src = 'images/test.jpg' /><img src = 'http://test.com/images/test3.jpg'/><video controls="controls" src='../videos/movie.ogg'></video></body></html>";

And I would like to turn it into:

$string2 = "<html><body><img src = 'test.jpg' /><img src = 'test3.jpg'/><video controls="controls" src='movie.ogg'></video></body></html>";

Heres what I tried :

$string2 = preg_replace("/src=["']([/])(.*)?["'] /", "'src=' . convert_url('$1') . ')'" , $string2);
echo htmlentities ($string2);

Basically it didn’t change anything and gave me a warning about unescaped string.

Doesn’t $1 send the content of the string ? What is wrong here ?

And the function of convert_url is from an example I posted here before : 

function convert_url($url)
{
    if (preg_match('#^https?://#', $url)) {
        $url = parse_url($url, PHP_URL_PATH);
    }
    return basename($url);
}

It’s supposed to strip out url paths and just return the filename.

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1 Answer

  1. Editorial Team

    You have to use the e modifier.

    $string = "<html><body><img src='images/test.jpg' /><img src='http://test.com/images/test3.jpg'/><video controls=\"controls\" src='../videos/movie.ogg'></video></body></html>";

$string2 = preg_replace("~src=[']([^']+)[']~e", '"src=\'" . convert_url("$1") . "\'"', $string);

    Note that when using the e modifier, the replacement script fragment needs to be a string to prevent it from being interpreted before the call to preg_replace.

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