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Editorial Team
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Asked: 2026-05-13T12:15:05+00:00

I’m trying to use the following code to access one byte with offset of

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I’m trying to use the following code to access one byte with offset of 50 bytes in a raw disk.

randomAccessFile = new RandomAccessFile("C:", "r");
randomAccessFile.seek(50);
byte[] buffer = new byte[1];
randomAccessFile.read(buffer);

But all what I get is the following error:

java.io.FileNotFoundException: C: (Acceso denegado)
at java.io.RandomAccessFile.open(Native Method)
at java.io.RandomAccessFile.<init>(RandomAccessFile.java:212)
at java.io.RandomAccessFile.<init>(RandomAccessFile.java:98)
at pru.lseek.main(lseek.java:26)

Is there any way to access a precise byte in a drive from java?

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1 Answer

  1. Editorial Team

    RandomAccessFile is not meant to open directories to manipulate entries, you need to create or remove files. “Acceso denegado” probably mean access denied.
    To do this anyway you need JNI.

    EDIT: What you are trying to do, is really complicated, there is no common way to do that. You can access the harddisc sector by sector, but then you would have to interpret it’s structure, which obviously depends on the file system, FAT,NTFS,HPFS etc.

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