Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6473669
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 25, 20262026-05-25T06:29:39+00:00 2026-05-25T06:29:39+00:00

I’m trying to use the google maps API to fetch direction times. I’m hoping

  • 0

I’m trying to use the google maps API to fetch direction times. I’m hoping to create a url, get the JSON response, and then examine that response for travel duration. After I create the JSON object, I have trouble navigating it. To me, this indicates that I have either messed up getting the response or navigating the JSON object. I’d appreciate it if you could peek at the bits and pieces of code I have stitched together from tutorials around the web.

This code is intended to get the response. It’s surrounded by a try/catch and it hasn’t triggered any errors.

      String stringUrl = <URL GOES HERE>;

      URL url = new URL(stringUrl);
      HttpURLConnection httpconn = (HttpURLConnection)url.openConnection();
      if (httpconn.getResponseCode() == HttpURLConnection.HTTP_OK)
      {
          BufferedReader input = new BufferedReader(new InputStreamReader(httpconn.getInputStream()),8192);
          String strLine = null;
          while ((strLine = input.readLine()) != null)
          {
              response.append(strLine);
          }
          input.close();
      }
      String jsonOutput = response.toString();

This code is intended to take that output and parse it into the final string, duration, as inspired by this stackoverflow answer for a similar question.

        JSONObject jsonObject = new JSONObject(jsonOutput);
        JSONObject routeObject = jsonObject.getJSONObject("routes");
        JSONObject legsObject = routeObject.getJSONObject("legs");
        JSONObject durationObject = legsObject.getJSONObject("duration"); 
        String duration = durationObject.getString("text");

I’m catching a JSON exception on the second line of the second block. Can anyone help to fix this? Or perhaps suggest a simpler way to get the same data?

EDIT: thanks to the first helpful answer here (from aromero), the latter half now looks like:

    JSONObject jsonObject = new JSONObject(responseText);
    JSONArray routeObject = jsonObject.getJSONArray("routes");
    JSONArray legsObject = routeObject.getJSONArray(2); ***error***
    JSONObject durationObject = legsObject.getJSONObject(1);
        String duration = durationObject.getString("text");

But it is still throwing a JSON exception, only now it’s after the third line. I’m sure this is embarrassingly easy to fix, but I would really appreciate some help.

The relevant part of an example JSON file is shown below:

{
   "routes" : [
      {
         "bounds" : {
            "northeast" : {
               "lat" : 34.092810,
               "lng" : -118.328860
            },
            "southwest" : {
               "lat" : 33.995590,
               "lng" : -118.446040
            }
         },
         "copyrights" : "Map data ©2011 Google",
         "legs" : [
            {
               "distance" : {
                  "text" : "12.9 mi",
                  "value" : 20807
               },
               "duration" : {
                  "text" : "27 mins",
                  "value" : 1619
               },
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-25T06:29:39+00:00Added an answer on May 25, 2026 at 6:29 am

    “routes” is an array, instead of using getJSONObject, use getJSONArray

    “legs” is an array also.

    JSONObject jsonObject = new JSONObject(responseText);
    
    // routesArray contains ALL routes
    JSONArray routesArray = jsonObject.getJSONArray("routes");
    // Grab the first route
    JSONObject route = routesArray.getJSONObject(0);
    // Take all legs from the route
    JSONArray legs = route.getJSONArray("legs");
    // Grab first leg
    JSONObject leg = legs.getJSONObject(0);
    
    JSONObject durationObject = leg.getJSONObject("duration");
    String duration = durationObject.getString("text");
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I'm making a simple page using Google Maps API 3. My first. One marker
Basically, what I'm trying to create is a page of div tags, each has
I am trying to understand how to use SyndicationItem to display feed which is
I am trying to render a haml file in a javascript response like so:
I'm trying to use string.replace('’','') to replace the dreaded weird single-quote character: ’ (aka
I'm trying to create an if statement in PHP that prevents a single post
link Im having trouble converting the html entites into html characters, (&# 8217;) i
I have a string like this: La Torre Eiffel paragonata all&#8217;Everest What PHP function
I want use html5's new tag to play a wav file (currently only supported
I'm parsing an RSS feed that has an &#8217; in it. SimpleXML turns this

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.