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Home/ Questions/Q 6224455
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T08:40:32+00:00 2026-05-24T08:40:32+00:00

I’m trying to use the ISHFT() function to bitshift some 32-bit integers in parallel,

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I’m trying to use the ISHFT() function to bitshift some 32-bit integers in parallel, using CUDA FORTRAN.

The problem is that I get different answers to ISHFT(-4,-1) and ISHFT(var,-1) even though var = -4. This is the test code I’ve written:

module testshift 

  integer :: test 
  integer, device :: d_test 

contains 

  attributes(global) subroutine testshft () 
    integer :: var
    var = -4
    d_test = ISHFT(var,-1)
  end subroutine testshft

end module testshift

program foo 
  use testshift 

  integer :: i
  call testshft<<<1,1>>>() ! carry out ishft on gpu
  test = d_test            ! copy device result to host
  i = ISHFT(-4,-1)         ! carry out ishft on cpu
  print *, i, test         ! print the results
end program foo

I then compile and execute:

pgf90 testishft.f90 -Mcuda
./a.out 
   2147483646           -2

Both should be 2147483646 if working correctly. I get the right answer if I replace var with 4.

How do I fix this problem?
Thanks for the help

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T08:40:32+00:00Added an answer on May 24, 2026 at 8:40 am

    I’ve found a workaround, which is posted in this forum:
    http://www.pgroup.com/userforum/viewtopic.php?t=2455&postdays=0&postorder=asc&start=15

    Instead of using ISHFT I use IBITS, which is described here: http://gcc.gnu.org/onlinedocs/gfortran/IBITS.html

    Also the problem has since been fixed in version 11.3 of the PGI compiler
    http://www.pgroup.com/support/release_tprs_2011.htm

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