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Home/ Questions/Q 6795737
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T18:22:58+00:00 2026-05-26T18:22:58+00:00

I’m trying to use the sort feature when querying my mongoDB, but it is

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I’m trying to use the sort feature when querying my mongoDB, but it is failing. The same query works in the MongoDB console but not here. Code is as follows:

import pymongo

from  pymongo import Connection
connection = Connection()
db = connection.myDB
print db.posts.count()
for post in db.posts.find({}, {'entities.user_mentions.screen_name':1}).sort({u'entities.user_mentions.screen_name':1}):
    print post

The error I get is as follows:

Traceback (most recent call last):
  File "find_ow.py", line 7, in <module>
    for post in db.posts.find({}, {'entities.user_mentions.screen_name':1}).sort({'entities.user_mentions.screen_name':1},1):
  File "/Library/Python/2.6/site-packages/pymongo-2.0.1-py2.6-macosx-10.6-universal.egg/pymongo/cursor.py", line 430, in sort
  File "/Library/Python/2.6/site-packages/pymongo-2.0.1-py2.6-macosx-10.6-universal.egg/pymongo/helpers.py", line 67, in _index_document
TypeError: first item in each key pair must be a string

I found a link elsewhere that says I need to place a ‘u’ infront of the key if using pymongo, but that didn’t work either. Anyone else get this to work or is this a bug.

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  1. Editorial Team
    Editorial Team
    2026-05-26T18:22:58+00:00Added an answer on May 26, 2026 at 6:22 pm

    .sort(), in pymongo, takes key and direction as parameters.

    So if you want to sort by, let’s say, id then you should .sort("_id", 1)

    For multiple fields:

    .sort([("field1", pymongo.ASCENDING), ("field2", pymongo.DESCENDING)])
    
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