Question

I’m trying to use this script (which extracts the domain from a URL):

CREATE FUNCTION [dbo].[parseURL]  (@strURL varchar(1000))
RETURNS varchar(1000)
AS
BEGIN
IF CHARINDEX('http://',@strURL) > 0 OR CHARINDEX('https://',@strURL) > 0
SELECT @strURL = REPLACE(@strURL,'https://','')
SELECT @strURL = REPLACE(@strURL,'http://','')
SELECT @strURL = REPLACE(@strURL,'www','')
-- Remove everything after "/" if one exists
IF CHARINDEX('/',@strURL) > 0 (SELECT @strURL = LEFT(@strURL,CHARINDEX('/',@strURL)-1))    
RETURN @strURL
END

Using this SQL command:

SELECT COUNT(*) as theCount, dbo.parseURL(url) as url FROM hit
WHERE url IS NOT NULL
GROUP BY dbo.parsedomain(url)
ORDER BY thecount DESC

But I’m receiving this error:

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '[dbo].[parseURL] (@strURL varchar(1000)) RETURNS varchar(1000) AS BEGIN IF ' at line 1

I am relatively new to both SQL and MySQL, so not sure if the error is SQL-general or MySQL-specific. What am I missing?

Answer 1

Here’s the equivalent MySQL function:

DELIMITER $$

CREATE FUNCTION parseURL(strURL VARCHAR(200)) 
  RETURNS varchar(200) 
BEGIN

  IF INSTR(strURL, 'http://') > 0 OR INSTR(strURL, 'https://') > 0 THEN
    SET strURL = REPLACE(strURL,'https://','');
    SET strURL = REPLACE(strURL,'http://','');
    SET strURL = REPLACE(strURL,'www','');
    -- Remove everything after "/" if one exists
    IF INSTR(strURL, '/') > 0 THEN 
     SET strURL = LEFT(strURL, INSTR(strURL, '/')-1);
   END IF;
  END IF;

  RETURN strURL;
END

Use this query:

  SELECT COUNT(*) as theCount, 
         parseURL(url) as url 
    FROM hit
   WHERE url IS NOT NULL
GROUP BY parseURL(url)
ORDER BY thecount DESC