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Home/ Questions/Q 6031795
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T05:14:17+00:00 2026-05-23T05:14:17+00:00

I’m trying to user jquery to add/remove a class on a pair of divs

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I’m trying to user jquery to add/remove a class on a pair of divs which consist of a background images. The div/image is meant to act as a radio box for a pair of hidden radio boxes.

When clicking the div/image the script should apply the class ‘selected’ to the clicked div and remove it (if necessary) from the other; and select the appropriate hidden radio button.

To the best of my knowledge the below script should work, but isn’t and I’m not really sure what I’m doing incorrectly right now. Any ideas stackers?

SCRIPT

$("div#like").click(function() {
    var $radios = $('input:radio[name=vote]');
    $("div#dislike").removeClass("selected");
    $("div#like").addClass("selected");
        $radios.filter('[value=likes]').attr('checked', true);
});

$("div#dislike").click(function() {
    var $radios = $('input:radio[name=vote]');
    $("div#like").removeClass("selected");
    $("div#dislike").addClass("selected");
        $radios.filter('[value=likes]').attr('checked', true);
});

HTML

<form action="createComment.php" method="post">
<div id="like" ><input class="like" type="radio" name="vote" value="likes" /></div>&nbsp;
<div id="dislike" ><input class="dislike" type="radio" name="vote" value="dislikes" /></div><br/>
</form>

[EDIT 3:07PM]
What if I went this route?

$("div#like").click(function() {
    var $radios = $('input:radio[name=vote]');
        $("div#dislike").removeClass("selected");
        $("div#like").addClass("selected");
        $radios.filter('[value=likes]').attr('checked', true);
        $radios.filter('[value=dislikes]').attr('checked', false);
    });

$("div#dislike").click(function() {
    var $radios = $('input:radio[name=vote]');
        $("div#like").removeClass("selected");
        $("div#dislike").addClass("selected");
        $radios.filter('[value=dislikes]').attr('checked', true);
        $radios.filter('[value=likes]').attr('checked', false);
    });
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T05:14:18+00:00Added an answer on May 23, 2026 at 5:14 am

    Don’t set the attribute checked="checked" using javascript. Instead, use

    radioButton.checked = true

    Using jquery you can do,

    $radios.filter('[value=likes]').get(0).checked = true
    

    Here is a nice little example for you, http://jsfiddle.net/cu2y8/6/

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