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Home/ Questions/Q 552383
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T11:29:38+00:00 2026-05-13T11:29:38+00:00

I’m trying to validate date using PHP. I’d like following formats to be valid:

  • 0

I’m trying to validate date using PHP.

I’d like following formats to be valid:

d/m/yy
d/m/yyyy
dd/m/yy
dd/m/yyyy
d/mm/yy
d/mm/yyyy
dd/mm/yy
dd/mm/yyyy

I’ve tried many regular expressions and different variations of checkdate() function. Currently I have something like this:

function _date_is_valid($str)
{
     if(strlen($str) == 0)
         return TRUE;
     if(substr_count($str,'/') == 2)
     {
         if (preg_match("/^((((31\/(0?[13578]|1[02]))|((29|30)\/(0?[1,3-9]|1[0-2])))\/(1[6-9]|[2-9]\d)?\d{2})|(29\/0?2\/(((1[6-9]|[2-9]\d)?(0[48]|[2468][048]|[13579][26])|((16|[2468][048]|[3579][26])00))))|(0?[1-9]|1\d|2[0-8])\/((0?[1-9])|(1[0-2]))\/((1[6-9]|[2-9]\d)?\d{2}))/", $str))
         {
             $datearray = explode('/',$str);
             if($datearray[2] > 2030)
                 return FALSE;
             return checkdate($datearray[1], $datearray[0], $datearray[2]);
         } 
         else 
         {
             return FALSE;
         }
     }
     return FALSE;
}

This however, validates dates like 11/11/200 and 11/11/200#

How can I validate date to match required format?

Edit: I could check datearray[2] to be between 10 and 30 and 2010 and 2030. But is there a way to check it using regex?

Edit1: return TRUE on strlen($str) == 0 is because I want users to be able to add events without knowing when will the event occur so someone else can qualify the schedule and assign event to certain date later


Just for the record. I ended up doing:

function _date_is_valid($str)
{
    if(strlen($str) == 0) //To accept entries without a date
        return TRUE;
    if(substr_count($str,'/') == 2)
    {
        list($d,$m,$y) = explode('/',$str);
        if(($y >= 10 && $y <= 30) || ($y >= 2010 && $y <= 2030))
        {
            return checkdate($m,$d,$y);
        }
    }
    return FALSE;
}

Thanks for all your answers

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T11:29:39+00:00Added an answer on May 13, 2026 at 11:29 am
    function _date_is_valid($str) {
        if (substr_count($str, '/') == 2) {
            list($d, $m, $y) = explode('/', $str);
            return checkdate($m, $d, sprintf('%04u', $y));
        }
    
        return false;
    }
    
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