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Home/ Questions/Q 8149935
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T14:57:00+00:00 2026-06-06T14:57:00+00:00

I’m trying to validate some form data before adding it to a database however

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I’m trying to validate some form data before adding it to a database however I need to validate that the option was an option that is in the form, not just one that was added with something like Firebug.

I tried using if and comparing the posted values like this: (there is another 27 options, and 3 more option fields)

if($data['selection'] == 'some_option' || $data['selection'] == 'some_option2') {

However it makes extremely long lines of code and its difficult to manage. So I thought about making an array that stores the possible options, then when its submitted, check if the selected option matches one of the entries in the array.

One of my ideas was to do a loop and check if it’s equal:

for($i = 1; $i < sizeof($options[$currentselection]); ++$i) {
    if($option[$i] == $data[$currentselection]) {
        return true;
    } else {
        return false;
    }
}

However I’d have to do one of these for each of the selection fields (which I’d rather not do). So is there a way of cleaning it up and having it all in one? Also, I’m using codeigniter.

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  1. Editorial Team
    Editorial Team
    2026-06-06T14:57:01+00:00Added an answer on June 6, 2026 at 2:57 pm

    A simple way is to use the in_array function

    $values=Array('op1','op2',...);
    return in_array($data['selection'],$values);
    

    Or you can do this:

    $values=Array(
      'selection'=>Array('op1','op2'),
      'another_field'=>Array('op3','op4'),
    );
    return in_array($data[$field],$values[$field]);
    
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