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Home/ Questions/Q 7171307
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T15:23:19+00:00 2026-05-28T15:23:19+00:00

I’m trying to wrap my head around Javascript’s function.apply(). You use it like this:

  • 0

I’m trying to wrap my head around Javascript’s function.apply(). You use it like this:
f.apply(obj,args)

to run function f with the given arguments args, with the function’s internal usage of this mapped onto the object obj.

Here’s a simple example to show how that all works to get us up-to-speed:

var o = { 
  state : 0, 
  plus : function(){
    this.state += 1;
  }
}
//o is an object with a state-tracking var and a function that will operate on it
o.state
// 0
o.plus()
o.state
// 1
newO = {state:3}
// newO  is similar to the original object, but doesn't have that state-manipulating function
newO.state
// 3
o.plus.apply(newO,[])  // call o's function, but hijack the 'this' reference to point to newO
newO.state
// 4

Cool. So I’ve written a function to solve a null pointer issue in javascript with a particular jquery plugin. If a jQuery set is empty, it just doesn’t run a function:

var applyIfPresent = function(jqObj,func,args){
  //only works if jquery has the func you supply
  if(jqObj.length){
    jqObj[func].apply(jqObj,args);
  }
}

I’ve run the simple test: applyIfPresent($("input"),"css",["background","blue"]);
To see if it’ll generalize to a jQuery set of multiple elements. It seems to work fine, but I have no idea how the internals of jQuery and the usage of this translates to that schema. I love that it seems to work like magic, but honestly?–I’ve learned to be a little afraid of magic.

How does f.apply or jQuery figure all that out to make it work?

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  1. Editorial Team
    Editorial Team
    2026-05-28T15:23:20+00:00Added an answer on May 28, 2026 at 3:23 pm

    it’s not that magic, you seem to understand it perfectly by the example above.
    when you do

    jqObj[func].apply(jqObj,args);
    

    it’s basically the same as doing

    $(jqObj).func(args);
    
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