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Home/ Questions/Q 6114869
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T15:01:33+00:00 2026-05-23T15:01:33+00:00

I’m trying to write a bash script which will behave as a basic interpreter,

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I’m trying to write a bash script which will behave as a basic interpreter, but it doesn’t seem to work: The custom interpreter doesn’t appear to be invoked. What am I doing wrong?

Here’s a simple setup illustrating the problem:

/bin/interpreter: [owned by root; executable]

#!/bin/bash

echo "I am an interpreter running " $1

/Users/zeph/script is owned by me, and is executable:

#!/bin/interpreter

Here are some commands for the custom interpreter.

From what I understand about the mechanics of hashbangs, the script should be executable as follows:

$ ./script
I am an interpreter running ./script

But this doesn’t work. Instead the following happens:

$ ./script 
./script: line 3: Here: command not found

…It appears that /bin/bash is trying to interpret the contents of ./script. What am I doing wrong?

Note: Although it appears that /bin/interpreter never invoked, I do get an error if it doesn’t exist:

$ ./script
-bash: ./script: /bin/interpreter: bad interpreter: No such file or directory

(Second note: If it makes any difference, I’m doing this on MacOS X).

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T15:01:34+00:00Added an answer on May 23, 2026 at 3:01 pm

    To make this work you could add the interpreter’s interpreter (i.e. bash) to the shebang:

    #!/bin/bash /bin/interpreter
    
    Here are some commands for the custom interpreter.
    

    bash will then run your interpreter with the script path in $1 as expected.

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