Question

Im trying to write a batch file which scans several files and looks for the string “WARNING“.
So far I have:

FORFILES -m*.f08 -C"CMD /C FINDSTR /N "WARNING"  ECHO @FILE >> ListOfWARNINGS

Problem one: It does not print each found string in a new line.

Problem two: How can I change the code and add a IF statement so that it also prints the line following the line where WARNING was found.

Answer 1

I think that for getting the next line your actually going to have to loop the files & content as neither forfiles nor find support this as far as I know;

@echo off
setlocal enabledelayedexpansion
for %%f in (*.txt) do (
    echo Search %%f
    for /f "usebackq eol= delims=] tokens=1*" %%l in (`find /n /v "" "%%f"`) do (
        set line=%%m
        if !printnext!==1 (
            echo.%%m >> ListOfWARNINGS
            set printnext=0
        ) else (
            if not [!line!]==[] if not !line!==!line:WARNING=X! (
                echo %%m >> ListOfWARNINGS
                set printnext=1
            ) else (
                set printnext=0
            )
        )
    )
)

Here if not !line!==!line:WARNING=X! detects a match by asking if a line is equal to itself after WARNING is replaced with X.

C:\null>type a.txt

line 1
M O D E L S U M M A R Y
WARNING XXXXXXX
Line after warning
NUMBER OF CBAR ELEMENTS = 18655
lorem ipsum lorem ipsum lorem ipsum
WARNING ZZZZZZZ


C:\null>x.bat
Search a.txt

C:\null>type ListOfWARNINGS
WARNING XXXXXXX
Line after warning
WARNING ZZZZZZZ

C:\null>