I’m trying to write a byteswap routine for a C++ program running on Win XP. I’m compiling with Visual Studio 2008. This is what I’ve come up with:
int byteswap(int v) // This is good
{
return _byteswap_ulong(v);
}
double byteswap(double v) // This doesn't work for some values
{
union { // This trick is first used in Quake2 source I believe :D
__int64 i;
double d;
} conv;
conv.d = v;
conv.i = _byteswap_uint64(conv.i);
return conv.d;
}
And a function to test:
void testit() {
double a, b, c;
CString str;
for (a = -100; a < 100; a += 0.01) {
b = byteswap(a);
c = byteswap(b);
if (a != c) {
str.Format("%15.15f %15.15f %15.15f", a, c, a - c);
}
}
}
Getting these numbers not matching:
-76.789999999988126 -76.790000000017230 0.000000000029104 -30.499999999987718 -30.499999999994994 0.000000000007276 41.790000000014508 41.790000000029060 -0.000000000014552 90.330000000023560 90.330000000052664 -0.000000000029104
This is after having read through:
How do I convert between big-endian and little-endian values in C++?
Little Endian – Big Endian Problem
You can’t use << and >> on double, by the way (unless I’m mistaken?)
Try 3
Okay, found out there’s a better way. The other way you have to worry about the order you pack/unpack stuff. This way you don’t:
Send:
Recv: