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Home/ Questions/Q 4023316
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T10:35:01+00:00 2026-05-20T10:35:01+00:00

I’m trying to write a code that converts a number to binary, and this

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I’m trying to write a code that converts a number to binary, and this is what I wrote. It gives me couple of errors in Eclipse, which I don’t understand.
What’s wrong with that? Any other suggestions? I’d like to learn and hear for any comments for fixing it. Thank you.

public class NumberConverte {
  public static void main(String[] args) {
    int i = Integer.parseInt(args);
    public static void Binary(int int1){
      System.out.println(int1 + "in binary is");
      do {
        System.out.println(i mod 2);
      } while (int1>0);
    }
  }
}

The error messages:

  1. The method parseInt(String) in the type Integer is not applicable for the arguments (String[])
  2. Multiple markers at this line
    • Syntax error on token “(“, ; expected
    • Syntax error on token “)“, ; expected
    • void is an invalid type for the variable Binary
  3. Multiple markers at this line
    • Syntax error on token “mod”, invalid AssignmentOperator
    • Syntax error on token “mod”, invalid AssignmentOperator.
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T10:35:02+00:00Added an answer on May 20, 2026 at 10:35 am

    Integer.toBinaryString(int) should do the trick !

    And by the way, correct your syntax, if you’re using Eclipse I’m sure he’s complaining about a lot of error.

    Working code :

    public class NumberConverter {
       public static void main(String[] args) {
           int i = Integer.parseInt(args[0]);
           toBinary(i);
       }
    
       public static void toBinary(int int1){
           System.out.println(int1 + " in binary is");
           System.out.println(Integer.toBinaryString(int1));
       }
    }
    
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