Question

Im trying to write a function that creates set of dynamic sublists each containing 5 elements from a list passed to it.Here’s my attempt at the code

def sublists(seq):
    i=0
    x=[]
    while i<len(seq)-1:
        j=0
        while j<5:
            X.append(seq[i]) # How do I change X after it reaches size 5?
     #return set of sublists

EDIT:

Sample input: [1,2,3,4,5,6,7,8,9,10]

Expected output: [[1,2,3,4,5],[6,7,8,9,10]]

Answer 1

Well, for starters, you’ll need to (or at least should) have two lists, a temporary one and a permanent one that you return (Also you will need to increase j and i or, more practically, use a for loop, but I assume you just forgot to post that).

EDIT removed first code as the style given doesn’t match easily with the expected results, see other two possibilities.

Or, more sensibly:

def sublists(seq):
    x=[]
    for i in range(0,len(seq),5):
        x.append(seq[i:i+5])
    return x

Or, more sensibly again, a simple list comprehension:

def sublists(seq):
    return [seq[i:i+5] for i in range(0,len(seq),5)]

When given the list:

l = [1,2,3,4,5,6,7,8,9,10]

They will return

[[1, 2, 3, 4, 5], [6, 7, 8, 9, 10]]