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Home/ Questions/Q 8060021
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T09:51:11+00:00 2026-06-05T09:51:11+00:00

I’m trying to write a function that validates an IPv4 address. Everything appears ok

  • 0

I’m trying to write a function that validates an IPv4 address.

Everything appears ok but it doesn’t appear to pick up the correct class.

My code is here: http://jsfiddle.net/felix001/X7EuJ/23/

<label for="input">IP</label>
<input type="text" name="input"  id="input" size="22" />
<input type="submit" value="submit" "whatmask_input" id="submit"  align="right" />

JavaScript:

function ipv4addr(x) {
    var REGEX = /^(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)$/;
    if ($x != $REGEX) {
        $("#input").addClass(".bad");
    }
    else {
        $("#input").addClass(".good");
    }
}

$(document).ready(function() {
    $("#submit").click(ipv4addr("#input"));

});

Could anyone tell me the best way to troubleshoot this issue?

Thanks,

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T09:51:13+00:00Added an answer on June 5, 2026 at 9:51 am

    Load your browser’s development tools console (eg, in Chrome) while you have the fiddler page open.

    The first error is:

    ReferenceError: Can't find variable: $x
    

    There is no need to prefix variable names with a $, $foo and foo are two different variable names. If you have var foo, then foo is the variable name.

    And looking at the code, this probably doesn’t do what you expect:

    $("#submit").click(ipv4addr("#input"));
    

    That would be the same as:

    var result = ipv4addr("#input");
    $("#submit").click(result);
    

    That is, pass the return value of calling ipv4addr (which is always undefined) into the click method. You probably want to pass a function to get called on every click instead.

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