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Home/ Questions/Q 8717395
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T06:17:44+00:00 2026-06-13T06:17:44+00:00

I’m trying to write a function that will take an array on input and

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I’m trying to write a function that will take an array on input and return array of arrays, containing all possible subsets of input array (power set without empty element). For example for input: [1, 2, 3] the result would be [[1], [2], [3], [1, 2], [1, 3], [2, 3], [1, 2, 3]].

This function does the job in python:

def list_powerset(lst):
    result = [[]]
    for x in lst:
        result += [subset + [x] for subset in result]
    result.pop(0)
    return result

But I’m looking for implementation of it in Delphi. Is this possible to accomplish this way or should I look for something else?

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  1. Editorial Team
    Editorial Team
    2026-06-13T06:17:45+00:00Added an answer on June 13, 2026 at 6:17 am
    type
      TIdArray = array of Integer;
      TPowerSet = array of TIdArray;
    
    function PowerSet(Ids: TIdArray): TPowerSet;
    // Implementation loosely based on the explanation on
    // http://www.mathsisfun.com/sets/power-set.html
    var
      TotalCombinations: Integer;
      TotalItems: Integer;
      Combination: Integer;
      SourceItem: Integer;
      ResultItem: Integer;
      Bit, Bits: Integer;
    begin
      TotalItems := Length(Ids);
    
      // Total number of combination for array of n items = 2 ^ n.
      TotalCombinations := 1 shl TotalItems;
    
      SetLength(Result, TotalCombinations);
    
      for Combination := 0 to TotalCombinations - 1 do
      begin
        // The Combination variable contains a bitmask that tells us which items
        // to take from the array to construct the current combination.
        // Disadvantage is that because of this method, the input array may contain
        // at most 32 items.
    
        // Count the number of bits set in Combination. This is the number of items
        // we need to allocate for this combination.
        Bits := 0;
        for Bit := 0 to TotalItems - 1 do
          if Combination and (1 shl Bit) <> 0 then
            Inc(Bits);
    
        // Allocate the items.
        SetLength(Result[Combination], Bits);
    
        // Copy the right items to the current result item.
        ResultItem := 0;
    
        for SourceItem := 0 to TotalItems - 1 do
          if Combination and (1 shl SourceItem) <> 0 then
          begin
            Result[Combination][ResultItem] := Ids[SourceItem];
            Inc(ResultItem);
          end;
      end;
    
    end;
    
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