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Home/ Questions/Q 7636503
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T07:41:53+00:00 2026-05-31T07:41:53+00:00

I’m trying to write a function to traverse a tree with depth first search.

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I’m trying to write a function to traverse a tree with depth first search.

My current algorithm goes something like:

If children
 go to first child

If no children
 go to next sibling

If no siblings
 go to parent

The problem I’m running into is that I can’t mark nodes on the tree as having been visited, so when I go to the parent the cycle just resets and it goes to the child again, getting stuck in a loop. Does anyone have any idea as to how I could solve this?

(It’s in java using the ANTLR plugin)

EDIT:

Following one of the suggestions I wrote this:

public void traverseTree(Tree tree){

    if (tree.getChildCount() > 0){
        tree = tree.getChild(0);
        traverseTree(tree);
        System.out.println(tree.toString());
    }
    if (tree.getParent().getChild(tree.getChildIndex() + 1) != null){
        tree = tree.getParent().getChild(tree.getChildIndex() + 1);
        traverseTree(tree);
        System.out.println(tree.toString());
    }
    if (!tree.getParent().toString().contains("ROOT_NODE")){
        tree = tree.getParent();
        traverseTree(tree);
        System.out.println(tree.toString());
    }
}

Root node is the name of the root node, but I’m getting a stack overflow error. Anyone have any idea why?

Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T07:41:54+00:00Added an answer on May 31, 2026 at 7:41 am

    I would use recursion in this case.

    class Node {
       public List<Node> getChildren() { .... }
    
       public void traverse(Visitor<Node> visitor) {
          // If children
          // go to first child - by traversing the children first.
           for(Node kid: getChildren())
               kid.traverse(visitor);
               // If no children
               //  go to next sibling, - by continuing the loop.
    
           visitor.visit(this);
           // If no siblings
           // go to parent - by returning and letting the parent be processed
       }
    }
    
    
    interface Vistor<N> {
       public void visit(N n);
    }
    
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