Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8796629
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 13, 20262026-06-13T23:40:02+00:00 2026-06-13T23:40:02+00:00

I’m trying to write a pair of functions, dt and ut , that convert

  • 0

I’m trying to write a pair of functions, dt and ut, that convert back and forth between normal unix time (seconds since 1970-01-01 00:00:00 UTC) and a Python datetime object.

If dt and ut were proper inverses then this code would print the same timestamp twice:

import time, datetime

# Convert a unix time u to a datetime object d, and vice versa
def dt(u): return datetime.datetime.fromtimestamp(u)
def ut(d): return time.mktime(d.timetuple())

u = 1004260000
print u, "-->", ut(dt(u))

Alas, the second timestamp is 3600 seconds (an hour) less than the first.
I think this only happens for very particular unixtimes, maybe during that hour that daylight savings time skips over.
But is there a way to write dt and ut so they’re true inverses of each other?

Related question: Making matplotlib's date2num and num2date perfect inverses

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-13T23:40:03+00:00Added an answer on June 13, 2026 at 11:40 pm

    You are correct that this behavior is related to daylight savings time. The easiest way to avoid this is to ensure you use a time zone without daylight savings, UTC makes the most sense here.

    datetime.datetime.utcfromtimestamp() and calendar.timegm() deal with UTC times, and are exact inverses.

    import calendar, datetime
    
    # Convert a unix time u to a datetime object d, and vice versa
    def dt(u): return datetime.datetime.utcfromtimestamp(u)
    def ut(d): return calendar.timegm(d.timetuple())
    

    Here is a bit of explanation behind why datetime.datetime.fromtimestamp() has an issue with daylight savings time, from the docs:

    Return the local date and time corresponding to the POSIX timestamp,
    such as is returned by time.time(). If optional argument tz is None or
    not specified, the timestamp is converted to the platform’s local date
    and time, and the returned datetime object is naive.

    The important part here is that you get a naive datetime.datetime object, which means there is no timezone (or daylight savings) information as a part of the object. This means that multiple distinct timestamps can map to the same datetime.datetime object when using fromtimestamp(), if you happen to pick times that fall during the daylight savings time roll back:

    >>> datetime.datetime.fromtimestamp(1004260000) 
    datetime.datetime(2001, 10, 28, 1, 6, 40)
    >>> datetime.datetime.fromtimestamp(1004256400)
    datetime.datetime(2001, 10, 28, 1, 6, 40)
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I'm parsing an RSS feed that has an ’ in it. SimpleXML turns this
I'm trying to create an if statement in PHP that prevents a single post
I am trying to understand how to use SyndicationItem to display feed which is
Basically, what I'm trying to create is a page of div tags, each has
link Im having trouble converting the html entites into html characters, (&# 8217;) i
That's pretty much it. I'm using Nokogiri to scrape a web page what has
I have a string like this: La Torre Eiffel paragonata all’Everest What PHP function
I've got a string that has curly quotes in it. I'd like to replace
I have a small JavaScript validation script that validates inputs based on Regex. I
I am trying to render a haml file in a javascript response like so:

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.