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Home/ Questions/Q 6775635
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T15:55:48+00:00 2026-05-26T15:55:48+00:00

I’m trying to write a regex in python to parse a Newick tree, but

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I’m trying to write a regex in python to parse a Newick tree, but for the life of me I can’t get the last part of it to match. There are three types of Newick formats I need to parse:

((A,B),C);
((A:0.1,B:0.2),C:0.3);
((A:[c1]0.1,B:[c2]0.2),C:[c2]0.3);

…each of which contains three labels (A, B, C) and various other bits of information. I want to get the three labels. Here’s my regex:

regex = re.compile(r"""
(
    ([,(])              # boundary
    ([A-Z0-9_\-\.]+)    # label
    (:)?                # optional colon
    (\[.+?\])?          # optional comment chunk
    (\d+\.\d+)?         # optional branchlengths
    ([),])              # end!
)
""", re.IGNORECASE + re.VERBOSE + re.DOTALL)

… however, I only get A and C. Not ever B. I’ve tracked the glitch down to the last captured group ([),]) – if I remove this, then I get all A, B, and C. Please help – what’s going wrong here?!

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  1. Editorial Team
    Editorial Team
    2026-05-26T15:55:48+00:00Added an answer on May 26, 2026 at 3:55 pm

    The problem is probably that you’re looking for non-overlapping instances of the regex.
    Methods like findall won’t return B as the match for A consumes the , before B.

    >>> regex.findall("((A:[c1]0.1,B:[c2]0.2),C:[c2]0.3);")
    [('(A:[c1]0.1,', '(', 'A', ':', '[c1]', '0.1', ','), (',C:[c2]0.3)', ',', 'C', ':', '[c2]', '0.3', ')')]
    

    Changing the end pattern to look ahead (so that it doesn’t consume anything) solves the problem.

    >>> regex = re.compile(r"""
    ... (
    ...     ([,(])              # boundary
    ...     ([A-Z0-9_\-\.]+)    # label
    ...     (:)?                # optional colon
    ...     (\[.+?\])?          # optional comment chunk
    ...     (\d+\.\d+)?         # optional branchlengths
    ...     (?=[),])            # end!
    ... )
    ... """, re.IGNORECASE + re.VERBOSE + re.DOTALL)
    >>>
    >>> regex.findall("((A:[c1]0.1,B:[c2]0.2),C:[c2]0.3);")
    [('(A:[c1]0.1', '(', 'A', ':', '[c1]', '0.1'), (',B:[c2]0.2', ',', 'B', ':', '[c2]', '0.2'), (',C:[c2]0.3', ',', 'C', ':
    ', '[c2]', '0.3')]
    >>>
    

    Otherwise, instead of using findall, you can use search iteratively and monkey with the pos argument.

    Something like this:

    >>> x = "((A:[c1]0.1,B:[c2]0.2),C:[c2]0.3);"
    >>> r = []
    >>> index = 0
    >>> while True:
    ...     m = regex.search(x, index)
    ...     if not m:
    ...        break
    ...     r.append(m.groups())
    ...     index = m.end(7)-1
    ...
    >>> r
    [('(A:[c1]0.1,', '(', 'A', ':', '[c1]', '0.1', ','), (',B:[c2]0.2)', ',', 'B', ':', '[c2]', '0.2', ')'), (',C:[c2]0.3)',
     ',', 'C', ':', '[c2]', '0.3', ')')]
    
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