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Home/ Questions/Q 669983
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T00:12:46+00:00 2026-05-14T00:12:46+00:00

I’m trying to write a short function that will let me quickly read in

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I’m trying to write a short function that will let me quickly read in a file of unknown size and return pointer to the array of data and the length of that array but it seems my code isn’t working. What am i doing wrong?

int readIn(int* pointer, param parameters, string description)
{
    string fileName = parameters.fileName + " " + description + ".bin";

    ifstream readFile;
    readFile.open(fileName.c_str(), ios::in|ios::binary|ios::ate);  

    int size = readFile.tellg();
    int length = size / 4;
    int* output = new int [length];

    readFile.seekg (0, ios::beg);
    readFile.read(reinterpret_cast<char*>(output), (size));
    readFile.close();

    pointer = output; // link new array with the pointer
    return length;
}

and in the main function:

int* testList;
int numEntries = readIn(testList, parameters, "test");

I end up with an error saying that my testList variable was used and not initialized. What am i doing wrong?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T00:12:46+00:00Added an answer on May 14, 2026 at 12:12 am

    You aren’t returning anything in your pointer variable after the function call.

    You can fill a variable so it’s value remains changed after the function call by dereferencing it’s address.

    Example:

    void fillX(int *p)
    {
      //p holds a memory address, go to that memory address and change its value
      *p = 4;
    }
    
    
    void main(int argc, char **argv)
    {
      int x;
      fillX(&x);
      return 0;
      assert(x == 4);
    }
    

    To change what a pointer points to you need to pass in a pointer to a pointer.

    I.e. you’d need to pass in the address of your pointer, and then you’d need the parameter type to be an int** pointer. When you set it you’d say *pointer = buffer;

    Example:

    void fillPointer(int **pp)
    {
      //p holds a memory address to a pointer 
      //Go to that memory address and change its value
      *pp = new int[10];
    }
    
    
    void main(int argc, char **argv)
    {
      int *x;
      fillPointer(&x);
      //x now points to the first element of an array
      delete[] x;
      return 0;
    }
    

    The key point here: When you want to change values via a parameter, you need to pass in it’s address, then dereference it to set what’s at that address.

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