Question

i’m trying to write a simple code for my project
if user types

walk 10

i need to use “walk” command in my walk(distance) method as distance = 10
i have something like that

while (!quit) {
Scanner in = new Scanner(System.in);
String input = in.nextLine();
// if (walk x is typed) {
walk(x);
}
}

i’m using java.util.scanner
and another problem is that my method walk(int x) uses int
so i need to convert String input to int

i searched the web for a while but couldnt find what i’m looking for (or i didnt understand it)

so anyway i’d appreciate if you can help me thanks

Thanks a lot for all the answers my initial problem is fixed
but now i have another problem
when i type just “walk” it gets array out of bounds exception
of course because it tries to convert null to an int (not possible)
i tried this and checked online

                    try {
                    Integer.parseInt(splitStrings[1]);
                    }
                    catch(NumberFormatException e) {
                    System.out.println("error: " + e);
                    }

still no help (i’m not good with try/catches)
so if user types walk without a distance i need to give an error message
thanks a lot again

ok i got it too
just used a simple thing

            if ("walk".equals(splitStrings[0])) {
                if (splitStrings.length == 2) {
                int distance = Integer.parseInt(splitStrings[1]);
                Robot.walk(distance);
                }
                if (splitStrings.length != 2) {
                    System.out.println("Entry must be like walk 10");
                }
            }

Answer 1

Try using the split() method on a string. It will return an array of Strings. For example

String s = 'walk 10';
String[] splitStrings = s.split(" ")

Now, to access 10, you can do this:

String distanceToWalk = splitStrings[1]

To convert it to an int, use the parseInt() method on Integer

Integer.parseInt(distanceToWalk);

See

1. http://docs.oracle.com/javase/6/docs/api/java/lang/String.html#split%28java.lang.String%29
2. http://docs.oracle.com/javase/6/docs/api/java/lang/Integer.html#parseInt%28java.lang.String%29