Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 602093
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T16:47:07+00:00 2026-05-13T16:47:07+00:00

I’m trying to write a sql function to do something like: SELECT person.id, person.phonenumber

  • 0

I’m trying to write a sql function to do something like:

SELECT
    person.id, 
    person.phonenumber
FROM
    person INNER JOIN activity ON person.id = activity.personid
WHERE
    MAX(activity.activitydate) < DATE_SUB(CURDATE(), INTERAVAL 180 DAY);

Each time a person is contacted, we create an activity record for them with notes and the like. So I’m looking for all of the people, who haven’t been contacted in the last 180 days. Obviously, this doesn’t work, as max can’t be used in the where clause.

I saw this, but mysql doesn’t have the with statement.

Additionally, I tried

SELECT 
    person.id, 
    person.phonenumber, 
    MAX(activity.activitydate) as ndate
FROM 
    person INNER JOIN activity ON person.id = activity.personid
WHERE 
    ndate < DATE_SUB(CURDATE(), INTERVAL 180 DAY)
GROUP BY person.id;

but ndate wasn’t known.

Any idea how I’d do this?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T16:47:08+00:00Added an answer on May 13, 2026 at 4:47 pm

    You need to use the HAVING clause:

      SELECT p.id, 
             p.phonenumber
        FROM PERSON p 
        JOIN ACTIVITY a ON a.personid = p.id
    GROUP BY p.id, p.phonenumber
      HAVING MAX(a.activitydate) < DATE_SUB(CURDATE(), INTERVAL 180 DAY)
    

    …which means defining a GROUP BY clause.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 409k
  • Answers 409k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer vcvarsall.bat is a batch file that comes with MSVC. Make… May 15, 2026 at 7:11 am
  • Editorial Team
    Editorial Team added an answer Edit: You can now use System.Windows.Input.Keybaord.IsKeyDown() see the other answers… May 15, 2026 at 7:11 am
  • Editorial Team
    Editorial Team added an answer If you want another response then you will have to… May 15, 2026 at 7:11 am

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.