Question

I’m trying to write a statement that will check 2 tables and compare the 2 and only show the users who are not on table2. For example:
table1 has user1, user2, user3, and user4 AND
table2 has user1, user3, and user4 then it would only show user2 in the list.

I was able to write something as basic as to only show member_id=’1′ but I don’t how to make it work the way I would like. I’m hoping you understand my question. I’ll include the short code that deals with this issue…

$sql->db_Select(DB_TABLE_ROSTER_MEMBERS, "*", "member_id='1' AND
                               (member_status like 'Team Member%'
                                OR member_status like 'Squad Leader%'
                                OR member_status like 'Recruiter%'
                                OR member_status like 'New Recruit%'$customArgs)
                               ORDER BY member_application_date DESC");

the syntax for this can be located here- http://wiki.e107.org/index.php?title=Db#db_Select.28.29
I’m guessing I just need to make another select DB and just have it included in the above so it would be something like

member_id != $member_id

where $member_id would be something like $member_id = $row[‘member_id’];

Answer 1

You need to make a LEFT JOIN and check where table2.member_id IS NULL.