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Home/ Questions/Q 8614833
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T05:13:03+00:00 2026-06-12T05:13:03+00:00

I’m trying to write a unit test against a single module function. This module

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I’m trying to write a unit test against a single module function. This module collaborates with a few other modules, so I’d like to mock those modules out to isolate my system under test. Here’s some simplified pseudo code:

local moduleFoo={}
local moduleBaz=  require("moduleBaz") 

moduleFoo.doSomething = function (arg) 

  if moduleBaz.bar.neatMethod(arg) then
     --does something interesting  
  end

end

return moduleFoo

And here’s the code for moduleBaz

local moduleBaz={}
moduleBaz.bar= {}

moduleBaz.bar.neatMethod=function(arg)
   --does something neat
end
return moduleBaz

I’m trying to use the package.preload function to inject a mock instance of moduleBaz before my tests run, but it doesn’t appear to work (i.e. the real instance of the moduleBaz is used in the test, not my mock)

Here’s some psueudo test code:

    package.loaded.moduleBaz= nil
    local moduleBaz = {}
    moduleBaz.bar = {}
    moduleBaz.bar.neatMethod= function(guid) return true end

    package.preload['moduleBaz'] = function ()
        return moduleBaz
    end

   local foo= require("moduleFoo")
   foo.doSomething('asdasdasda')--real moduleBaz is called, not my mock!

Any ideas what I’m doing wrong? I’m very new to Lua, and not at all comfortable with how scope is handled in the language!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T05:13:04+00:00Added an answer on June 12, 2026 at 5:13 am

    You seem to be missing a return statement in your moduleBaz code

    return moduleBaz
    

    Why not use package.loaded as it gives you a simpler interface? package.loaded.moduleBaz would simply need to include whatever you’d want to return from your moduleBaz code. Something like this should work or give you an idea:

    package.loaded.moduleBaz = {
      bar = {
        neatmethod = function(arg)
          -- your mock code here
        end,
      }
    }
    

    Then require('moduleBaz') would simply return that object you just created.

    I cannot reproduce the issue with your setup either. The files I used are below; notice that I added return moduleBaz as I described above, but this is the only change I made:

    file moduleBaz.lua:

    local moduleBaz={}
    moduleBaz.bar= {}
    moduleBaz.bar.neatMethod=function(arg)
      print "baz"
      return true
    end
    return moduleBaz
    

    file moduleFoo.lua:

    local moduleFoo={}
    local moduleBaz=  require("moduleBaz") 
      moduleFoo.doSomething = function (arg) 
      if moduleBaz.bar.neatMethod(arg) then
        print "foo"
      end
    end
    return moduleFoo
    

    file testFoo.lua

    package.loaded.moduleBaz= nil
    local moduleBaz = {}
    moduleBaz.bar = {}
    moduleBaz.bar.neatMethod= function(guid) print "mock" return true end
    
    package.preload['moduleBaz'] = function ()
        return moduleBaz
    end
    
    local foo= require("moduleFoo")
    foo.doSomething('asdasdasda')--real moduleBaz is called, not my mock!
    

    When I run this, I get mock\nfoo\n printed as expected.

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