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Home/ Questions/Q 973501
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T03:17:19+00:00 2026-05-16T03:17:19+00:00

I’m trying to write the contents of buf pointer to the file created by

  • 0

I’m trying to write the contents of buf pointer to the file created by ofstream.

For some reason the file is empty, however the contents of buf is never empty… What am I doing wrong?

void DLog::Log(const char *fmt, ...)
{
    va_list varptr;

    va_start(varptr, fmt);

    int n = ::_vscprintf(fmt, varptr);
    char *buf = new char[n + 1];
    ::vsprintf(buf, fmt, varptr);

    va_end(varptr);

    if (!m_filename.empty())
    {

        std::ofstream ofstr(m_filename.c_str(), ios::out);

        ofstr << *buf; // contents of *buf are NEVER empty, however nothing is in file??

        ofstr.close();
    }


    delete [] buf;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T03:17:20+00:00Added an answer on May 16, 2026 at 3:17 am

    Many problems can be solved by getting rid of the hairy stuff, like manual allocation management.

    Never use new T[N] in your code: instead use std::vector<T> v(N);. Simply this alone might solve your problem, because the pointer stuff isn’t in the way:

    void DLog::Log(const char *fmt, ...)
    {
        va_list varptr;
        va_start(varptr, fmt);
    
        int n = ::_vscprintf(fmt, varptr);
        std::vector<char> buf(n + 1);
    
        ::vsprintf(&buf[0], fmt, varptr);
    
        va_end(varptr);
    
        if (!m_filename.empty())
        {
            std::ofstream ofstr(m_filename.c_str(), ios::out);
            if (!ofstr) 
            {
                // didn't open, do some error reporting here
            }
    
            // copy each character to the stream
            std::copy(buf.begin(), buf.end(), std::ostream_iterator<char>(ofstr));
    
            // no need to close, it's done automatically
        }
    
        // no need to remember to delete
    }
    

    Much easier to read and maintain. Note even better would be a std::string buf(n + 1);, then you could just do ofstr << buf;. Sadly, std::string isn’t currently required to store its elements contiguously, like std::vector. This means the line with &buf[0] isn’t guaranteed to work. That said, I doubt you’ll find an implementation where it wouldn’t work. Still, it’s arguably better to maintain guaranteed behavior.

    I do suspect the issue was you dereferencing the pointer, though.

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