Question

I’m trying to write two inverse functions.
If we pass to function A value 10 it returns for example 4,86 and if we pass that number to function B it should give us back original 10.

I’m using something like this in function A:

output = sqrt(inputForA / range) * inputForA;

So is it possible to reverse it in function B and calculate inputForA only knowing output and range.

Answer 1

You just need to factor that equation to single out inputForA. Here are the algebraic steps:

output = sqrt(inputForA / range) * inputForA

output / inputForA = sqrt(inputForA / range)

sq(output) / sq(inputForA) = inputForA / range

range * sq(output) / sq(inputForA) = inputForA

range * sq(output) = cube(inputForA)

So the cube root of range times the output squared should give you your original input. I don’t have a good way of showing that in here though…