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Home/ Questions/Q 3486474
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T11:02:05+00:00 2026-05-18T11:02:05+00:00

I’m used to work with functional programming (mainly Haskell) and I’m beginning with OO

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I’m used to work with functional programming (mainly Haskell) and I’m beginning with OO (scala).

I’m having troubles on translating my code. For instance, that’s my Haskell definition of a B-tree:

data BTree a = 
    Leaf
    |Node2 (BTree a) a (BTree a)
    |Node3 (BTree a) a (BTree a) a (BTree a)
    deriving (Eq,Read,Show) 

It’s quite simple. My tree is empty, or it has a value and is a father of two trees or it is a father of 3 sub trees.

What is it on OO? I have no clue. I just can’t figure out how can I do it in a sane way.

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  1. Editorial Team
    Editorial Team
    2026-05-18T11:02:05+00:00Added an answer on May 18, 2026 at 11:02 am

    Since you have Scala in your tag-list, here is how it would be done in Scala:

    You have a base trait (in Haskell the type), and derived from that all the Haskell constructors as case classes. That way you can use them in Scala pattern matching as well.

    sealed trait Tree[+A]
    
    case object Leaf extends Tree[Any]
    case class Node2[+A](a: A,  t1: Tree[A], t2: Tree[A]) extends Tree[A]
    case class Node3[+A](a: A, b: A,  t1: Tree[A], t2: Tree[A], t2: Tree[A]) extends Tree[A]
    

    In languages like Java (since 1.5), C++ and C# you have the same kind of templates to help type safety. They basically work like the type variables in Haskell.

    This example is in Scala, but for other OO languages you would do it in a similar way: Create an abstract base class and turn the constructors of your data into classes/objects.

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