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Home/ Questions/Q 964047
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T01:45:59+00:00 2026-05-16T01:45:59+00:00

I’m using a basic registration form with AJAX, but the form is not connecting

  • 0

I’m using a basic registration form with AJAX, but the form is not connecting to the database. I’m obviously overlooking something.

So here’s the field I want to validate.

Username:<input type="text" name="user" id="user" maxlength="30">
<span id="msgbox" style="display:none"/></input>

Then I use jQuery, here’s the code:

$(document).ready(function() {
    $("#user").blur(function() {

        //remove all the class add the messagebox classes and start fading
        $("#msgbox").removeClass().addClass('messagebox').text('Checking...').fadeIn("slow");
        //check the username exists or not from ajax
        $.post("user_availability.php",{ user_name:$(this).val() },
            function(data) {
                if(data=='no') { //if username not avaiable
                    $("#msgbox").fadeTo(200,0.1,function() {//start fading the messagebox
                        //add message and change the class of the box and start fading
                        $(this).html('This User name Already exists').addClass('messageboxerror').fadeTo(900,1);
                    });       

                } else {
                    $("#msgbox").fadeTo(200,0.1,function() { //start fading the messagebox
                        //add message and change the class of the box and start fading
                        $(this).html('Username available to register').addClass('messageboxok').fadeTo(900,1);   
                    });
                } // else
             } // function

        ); // $.post
    }); // blur
}); // ready

And I have this code, user_availability.php:

mysql_connect(localhost,$user,$password);
    or die('There is error to connect to server:-'.mysqli_connect_error());

$db_selected = mysql_select_db($database);
$user_name=$_POST['user_name'];
$sql = "select * from members where username='$user_name'";
$result = mysql_query($sql);

while($row = mysql_fetch_assoc($result))   
{
    $existing_users[] = $row['username'];
}

if (in_array($user_name, $existing_users))
{
    echo "no"; //user name is not availble
}
else
{
    echo "yes"; //user name is available
}

I get no database errors. The form will be more substantial, but I can’t get it to work with this field. Any suggestions?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T01:46:00+00:00Added an answer on May 16, 2026 at 1:46 am

    Just a nitpick on the select statement. Since you only need to get how many rows exist for the entered username you don’t need to do a “select *” as depending on the number of columns in your users table you could be returning quite a bit of data. I would revise your query to be like so:

    $sql = "select COUNT(username) from members where username=$user_name";
    

    Then you check to make sure that the result of the query equals zero. If it does then the username is available.

    I know that the above wasn’t an answer to your question but just thought I would point it out since this looks to be a function that is going to get called a lot depending on the traffic on your registration form and the creativity of your visitors.

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